Answer:
(B) Vertically upward
Explanation:
r = Side of triangle = 14 cm
q = Charge = -2.5 nC
Electrical force is given by
[tex]F=\dfrac{kq_1q_2}{r^2}\\\Rightarrow F=\dfrac{8.99\times 10^9\times (2.5\times 10^{-9})^2}{0.14^2}\\\Rightarrow F=2.86671\times 10^{-6}\ N[/tex]
For the top charge
Net force on both charges is given by
[tex]F_n=2Fcos\theta\\\Rightarrow F_n=2\times 2.86671\times 10^{-6}\times cos30\\\Rightarrow F_n=4.96529\times 10^{-6}\ N[/tex]
The net force acting on the top charge is [tex]4.96529\times 10^{-6}\ N[/tex]
Here the forces are symmetrical hence, the net force is along +y axis i.e., upward
