Answer:
Explanation:
Given
Charge of [tex]Q=0.8\ nC[/tex]
Length of side of cube [tex]a=4\ m[/tex]
Total Flux through the cube [tex]\phi =\frac{Q}{\epsilon _0}[/tex]
[tex]\epsilon _0=8.854\times 10^{-12}\ C^2/N-m^2[/tex]
total Flux [tex]\phi=\frac{0.8\times 10^{-9}}{8.854\times 10^{-12}}[/tex]
[tex]\phi =90.35\ N-m^2/C[/tex]
As cube has 6 faces , so flux through each face will be similar
thus flux through each face [tex]\phi'=\frac{\phi }{6}[/tex]
[tex]\phi '=\frac{90.35}{6}=15\ N-m^2/C[/tex]
