Consider the function f(x) = 3x2 + 7x + 2.



What is the value of the discriminant?

How many x-intercepts does this function have?

What are the number of zeros for this function?

Respuesta :

The discriminant:
D = b² - 4 a c = 7² - 4· 3 · 2 = 49 - 24 = 25 
D > 0 This function has 2 x-intercepts ( 2 zeroes ).
x 1 = (-7+5)/6 =-1/3
x 2 = (-7-5) / 6 = - 2 

The value of the discriminant is 25. There are two x-intercepts and two real zeros.

How to derive the characteristics of a second order polynomial by quadratic formula

All roots of second order polynomial of the form [tex]a\cdot x^{2}+b\cdot x + c = 0[/tex] can be be found analytically by quadratic formula:

[tex]x_{1,2} = \frac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}[/tex], [tex]a, b, c\in \mathbb{R}[/tex]   (1)

Where [tex]b^{2}-4\cdot a\cdot c[/tex] is the discriminant. There are three scenarios:

  1. If discriminant is greater than zero, then the polynomial has two different real x-intercepts. Two real zeros.
  2. If discriminant is equal to zero, then the polynomial has two equal real x-intercepts. Two real zeros.
  3. If discriminant is less that zero, then the polynomial has no x-intercepts. Two conjugated complex zeros.

If we know that [tex]a = 3[/tex], [tex]b = 7[/tex] and [tex]c = 2[/tex], then the discriminant is:

[tex]d = 7^{2}-4\cdot (3)\cdot (2)[/tex]

[tex]d = 49-24[/tex]

[tex]d = 25[/tex]

The value of the discriminant is 25. There are two x-intercepts and two real zeros. [tex]\blacksquare[/tex]

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