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7. Two children of mass 20 kg and 30 kg sit balanced on a seesaw with the pivot point located at the center of the seesaw. If the children are separated by a distance of 3 m, at what distance from the pivot point is the small child sitting in order to maintain the balance?

Respuesta :

Answer:

Explanation:

Given

mass of children [tex]m_1=20\ kg[/tex]

[tex]m_2=30\ kg[/tex]

distance between two children [tex]L=3\ m[/tex]

suppose  small child is at a distance of x m from  pivot point

so torque of small child and heavier child must be equal

[tex]20\times (x)=30\times (3-x)[/tex]

[tex]2x=9-3x[/tex]

[tex]5x=9[/tex]

[tex]x=1.8\ m[/tex]    

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