Answer:
461.88 N
Explanation:
The swing is in static equilibrium. T is the tension in the string. Refer to the attached figure.
In the vertical direction:
[tex] T cos 30^o= mg = 800 N\\ \Rightarrow T = 923.76 N[/tex]
In the horizontal direction:
[tex] F= T sin 30^o\\ \Rightarrow F = (923.76 \times sin 30^o) N=461.88 N[/tex]
Thus, the horizontal force being applied by the partner is 461.88 N.
