Answer:
[tex]12x+3\leq 27[/tex]
Step-by-step explanation:
It is given that
[tex]9\geq4x+1[/tex]
We need to find the possible range of values of 12x+3.
Subtract -1 from both sides.
[tex]9-1\geq 4x[/tex]
[tex]8\geq 4x[/tex]
Multiply both sides by 3.
[tex]24\geq 12x[/tex]
Add 3 on both sides.
[tex]24+3\geq 12x+3[/tex]
[tex]27\geq 12x+3[/tex]
It can be rewritten as
[tex]12x+3\leq 27[/tex]
Therefore, 12x+3 must be less than or equal to 27.
