contestada

Given the following reaction:
[tex]C_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O[/tex]
How many moles of CO₂ ​will be produced from 79.0 g of C₃H₈, assuming O₂ is available in excess?

Respuesta :

anfabba15

Answer:

5.38 moles of CO₂ are produced

Explanation:

This is the reaction:

C₃H₈  +  5O₂  →  3CO₂  +  4H₂O

First of all, let's convert the mass of C₃H₈ to moles (mass / molar mass)

79 g / 44 g/mol = 1.79 moles

So ratio is 1:3.

1 mol of C₃H₈ is needed to produce  3 moles of CO₂

1.79 moles of C₃H₈ would produce (1.79  .3) /1 =  5.38 moles

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