Answer:
a)F=698.83 N
b)K=8221.56 N/m
Explanation:
Given that
mass ,m = 0.12 kg
Amplitude ,A= 8.5 cm
time period ,T = 0.2 s
We know that
[tex]T=\dfrac{2\pi}{\omega}[/tex]
[tex]{\omega}=\dfrac{2\pi }{0.2}\ rad/s[/tex]
[tex]{\omega}=31.41\ rad/s[/tex]
We know that
[tex]{\omega}^2=m\ K[/tex]
K=Spring constant
[tex]K=\dfrac{\omega^2}{m}[/tex]
[tex]K=\dfrac{31.41^2}{0.12}\ N/m[/tex]
K=8221.56 N/m
The maximum force F
F= K A
F= 8221.56 x 0.085 N
F=698.83 N
a)F=698.83 N
b)K=8221.56 N/m
