Answer:
The reactions are:
H₂SO₃ + H₂ O ⇄ HSO₃⁻ + H₃O⁺
HSO₃⁻ + H₂O ⇄ SO₃⁻² + H₃O⁺
Explanation:
This is the sulfurous acid → H₂SO₃.
It is a weak diprotic acid and it is diprotic because it can release 2 protons to increase H₃O⁺ from water. As every weak acid, the reactions are in equilibrium, that's why it has two Ka. As it can release protons, it is an acid from Bronsted Lowry and an acid from Arrhenius.
H₂SO₃ + H₂ O ⇄ HSO₃⁻ + H₃O⁺ Ka₁
HSO₃⁻ → this is called acid sulfite
HSO₃⁻ + H₂O ⇄ SO₃⁻² + H₃O⁺ Ka₂
2H₂O ⇄ H₃O⁺ + OH⁻ Kw
(Don't forget to put water equation, always)
The balanced chemical equations for the acid dissociation of sulfurous acid are:
Sulfurous acid is a polyprotic acid.
A polyprotic acid is an acid that can release more than one proton in an aqueous solution.
Sulfurous acid has 2 protons so it releases them in 2 steps.
H₂SO₃(aq) ⇄ HSO₃⁻(aq) + H⁺(aq)
HSO₃⁻(aq) ⇄ SO₃²⁺(aq) + H⁺(aq)
The balanced chemical equations for the acid dissociation of sulfurous acid are:
Learn more about polyprotic acids here: https://brainly.com/question/8965505
