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use the method of completing the square to write the equations of the given parabola in this form:
(y-k)=a(x-h)^2
where a =0, (h,k) is the vertex, and x=h is the axis of symmetry.
Find the vertex of this parabola: y=-4x^2+8x-12

Respuesta :

calculista

Answer:

The vertex is the point (1,-8)

Step-by-step explanation:

we have

[tex]y=-4x^{2} +8x-12[/tex]

Convert to vertex form

step 1

Group terms that contain the same variable, and move the constant to the opposite side of the equation

[tex]y+12=-4x^{2} +8x[/tex]

step 2

Factor the leading coefficient

factor -4

[tex]y+12=-4(x^{2} -2x)[/tex]

step 2

Complete the square. Remember to balance the equation by adding the same constants to each side

[tex]y+12-4=-4(x^{2} -2x+1)[/tex]

[tex]y+8=-4(x^{2} -2x+1)[/tex]

step 3

Rewrite as perfect squares

[tex]y+8=-4(x-1)^{2}[/tex]

therefore

The vertex is the point (1,-8)

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