Answer:
r = 3721.04 m
Explanation:
Given that,
Weight of human, F = 650 N
Charge on two humans, [tex]q_1=q_2=1\ C[/tex]
We need to find the distance between charges if the electric attraction between them to equal their 650 N weight. It is given by :
[tex]F=\dfrac{kq^2}{r^2}[/tex]
[tex]r=\sqrt{\dfrac{kq^2}{F}}[/tex]
[tex]r=\sqrt{\dfrac{9\times 10^9\times 1^2}{650}}[/tex]
r = 3721.04 m
So, the distance between charges is 3721.04 m if the electric attraction between them to equal their 650 N weight. Hence, this is the required solution.
