Monochromatic light falls on two very narrow slits 0.040 mm apart. Successive fringes on a screen 4.70 m away are 5.9 cm apart near the center of the pattern. What is the wavelength of the light?

Respuesta :

Answer:

λ = 502 n m

Explanation:

given,

slit separation,  d = 0.040 mm

                             = 4 x 10⁻⁵ m

Distance between the fringes, D = 4.70 m

distance between the fringes, x = 5.9 cm

                                                     = 0.059 m

wavelength of the light = ?

the separation between the fringe is given by

[tex]x = \dfrac{n\lambda\ D}{d}[/tex]

[tex]\lambda = \dfrac{x d}{n\ D}[/tex]

where as n = 1

[tex]\lambda = \dfrac{0.059\times 4\times 10^{-5}}{1\times 4.70}[/tex]

 λ = 5.02127 x 10⁻⁷ m

λ = 502 n m

hence, the wavelength of the light is equal to λ = 502 n m