The magnitude of the force of friction is 6.1 N
Explanation:
The work done by a force when moving an object is given by the equation:
[tex]W=Fd cos \theta[/tex]
where :
F is the magnitude of the force
d is the displacement
[tex]\theta[/tex] is the angle between the direction of the force and of the displacement
In this problem, we have:
W = -55.2 J (work done by the force of friction)
d = 8.98 m (displacement of the sled)
[tex]\theta=180^{\circ}[/tex] (because the force of friction acts opposite to the direction of motion)
By solving the equation for F, we find the magnitude of the force of friction on the sled:
[tex]F=\frac{W}{d cos \theta}=\frac{-55.2}{(8.98)(cos 180^{\circ})}=6.1 N[/tex]
Learn more about work:
brainly.com/question/6763771
brainly.com/question/6443626
#LearnwithBrainly
