Respuesta :
Answer:
It would take skinny cat 6 mins to reach fat cat.
Step-by-step explanation:
Given:
Speed of Fat cat = 75 yd/min
Speed of skinny cat = 100 yd/min
We need to find the time taken by skinny cat to reach fat cat.
Let the distance covered by both be 'd'.
Also let the time taken by Fat cat to cover distance 'd' be 't' mins.
Now we know that skinny cat started 2 mins later so time taken by Skinny cat will be [tex]t-2 \ mins[/tex].
Now we know that;
Distance is equal to speed times time.
framing in equation form we get;
Distance cover by fat cat = [tex]75t[/tex]
Distance cover by skinny cat = [tex]100(t-2) =100t-200[/tex]
Both distance have to made same since we need to find the time required more to reach the other cat.
[tex]100t-200=75t[/tex]
Combining like terms we get;
[tex]100t-75t=200\\\\25t =200[/tex]
Dividing both side by 25 we get;
[tex]\frac{25t}{25}=\frac{200}{25}\\\\t = 8\ mins[/tex]
Time taken by skinny cat = [tex]t-2 =8-2=6 \ mins[/tex]
Hence it would take skinny cat 6 mins to reach fat cat.
