Answer:
2.95 [tex]\times 10^{-9}[/tex] is the fraction of the nucleus is present in atom.
Explanation:
Given:
The diameter of the nucleus - 10A
The diameter of atom - 1.5 A
From this, we can find the radius of nucleus and atom i.e.
For nucleus [tex]=\frac{10}{2}[/tex]
For atom [tex]= \frac{1.5}{2}[/tex]
Now, the fraction of nucleus [tex]= \frac{volume of nucleus}{volume of atom}[/tex]
= [tex]\frac{4}{3}\pi (\frac{10}{2})\frac{3.14}{2}\pi (\frac{10}{2})^3[/tex]
or, = [tex](\frac{10}{1.5})^3[/tex]
= 2.95 [tex]\times 10^{-9}[/tex]
Therefore, 2.95 [tex]\times 10^{-9}[/tex] is the fraction of nucleus in the atom.
