Answer:
-2.89×[tex]10^{-49}[/tex]N
Explanation:
solution
sodium is + ion q1 = 1.602×[tex]10^{-19}[/tex]
chloride is - ion q2= -1.602×[tex]10^{-19}[/tex]
According to coulomb force of attraction
F = k * q1 * q2 / d2...........(1)
where,
k=-9×[tex]10^{9}[/tex]
distance between sodium and chloride ion d2=2.82×[tex]10^{-10}[/tex]
putting all these values k,q1,q2,d2 in eq (1) and solve then we get,
F= -2.89×[tex]10^{-49}[/tex]N
Note:
Negative sign indicates the force is attractive
