Answer:
0.0035 mL of oxygen per hour is metabolic rate at 20°C at cockroach.
Explanation:
From the data we can see that metabolic rate of cockroach is in direct relation with temperature.
[tex]Rate \propto Time[/tex]
On graph, with metabolic rate on y-axis and temperature on x axis straight line will obtained , and the equation of the line can be determined by the help of point slope:
[tex](y-y_1)=m(x-x_1)[/tex]
m = Slope of the line = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
As per information given , :
[tex](x_1,y_1) , (x_2,y_2) = (15,0.01) (25,0.015)[/tex]
[tex]m=\frac{0.015-0.01}{25-15}=\frac{0.005}{10}=0.0005[/tex]
[tex](y-0.01)=0.0005(x-15)[/tex]
[tex]y-0.001=0.0005x-0.0075[/tex]
[tex]y=0.0005x-0.0065[/tex]
x = temperature
y = metabolic rate
Now , put x = 20
[tex]y=0.0005\times 20-0.0065[/tex]
y = 0.0035
0.0035 mL of oxygen per hour is metabolic rate at 20°C at cockroach.
