Predict the mass of oxygen required to react with 14 g of nitrogen to make N2O5 if 16 g of oxygen reacts with 14 g of nitrogen to make N2O2.

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Answer:

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Explanation:

The mass of oxygen reacted with 14 g nitrogen has been 16 grams.

The formation of dinitrogen dioxide has been mediated with the reaction of oxygen with nitrogen.

Mass of Oxygen required

The mass of oxygen required for the reaction has been given with the balanced chemical equation as:

[tex]\rm N_2\;+\;O_2\;\rightarrow\;N_2O_2[/tex]

Thus, for the reaction with 1 mole of oxygen, 1 mole of nitrogen has been required.

The mass of 1 mole oxygen has been 32 g.

The mass of 1 mole nitrogen has been 28 g.

Thus, for the reaction with 14 g nitrogen, the mass of oxygen required has been:

[tex]\rm 28\g\;N_2=32\;g\;O_2\\14\;g\;N_2=\dfrac{32}{28}\;\times\;14\g\;O_2\\14\;g\;N_2=165\;g\;O_2[/tex]

The mass of oxygen reacted with 14 g nitrogen has been 16 grams.

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