Answer:
The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.
Step-by-step explanation:
let S be the sample space for the inspection of the light bulbs.
Therefore, n(s) = 800
let ' A ' be the event of no defects bulbs.
Therefore, n(A) = 796
Now the Experiment probability for a light bulb chosen has no defects will be given by,
[tex]P(A)=\dfrac{n(A)}{n(S)}[/tex]
Substituting the values we get
[tex]P(A)=\dfrac{796}{800}=0.995[/tex]
The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.
