Respuesta :
The answer is: They will interfere to create a trough with an amplitude of 6.
Answer:
[tex]A_r=6.[/tex]
Explanation:
It is given that both wave have same amplitude i.e [tex]A=3.[/tex]
Now, we need to find what will happen to the waves when trough of wave A meets the trough of wave B.
It means that both waves are in same phase i.e, the phase difference between them is 0 degree.
We know resultant amplitude [tex]A_r[/tex] of two waves of same amplitude A with phase difference [tex]\theta[/tex] is given by.
[tex]A_r=2\times A \times cos\dfrac{\theta}{2}.[/tex]
In this case , A=3 and [tex]\theta=0^o.[/tex]
Putting value of A and [tex]\theta[/tex] in above equation.
We get, [tex]A_r=6.[/tex]
Therefore, a new wave will form of resultant amplitude of 6.
Hence, it is the required solution.
