Answer:
V = 8.97×10⁴ L
Explanation:
Given data:
Mass of oxygen = 1.35×10⁵ g
Litters of oxygen = ?
Solution:
First of all we will calculate the number of moles.
Number of moles = mass/ molar mass
Number of moles = = 1.35×10⁵ g / 32 g/mol
Number of moles = 0.04 ×10⁵ mol
Litters of oxygen:
PV = nRT
V = nRT/P
V = 0.04 ×10⁵ mol × 0.0821 atm. L/ mol. K ×273 K / 1atm
V = 0.897×10⁵ atm.L / 1atm
V = 8.97×10⁴ L
Answer:
9.46 x 10⁴ L
Explanation:
Data Given:
mass of oxygen (O₂) = 1.35 x 10⁵
Liters of oxygen O₂ (volume) = ?
Solution:
First find no. of moles of oxygen
Formula used
no. of moles = mass in gram / molar mass
molar mass of oxygen (O₂) = 2(16)
molar mass of oxygen (O₂) = 32 g/mol
Put values in above formula
no. of moles = 1.35 x 10⁵ / 32 g/mol
no. of moles = 4219 mol
Now we will find volume of oxygen
Formula used
no. of moles = Volume of gas / Molar volume
Rearrange the above equation to find volume
Volume of gas = no. of moles x Molar Volume . . . . . . (1)
Where
Molar volume = 22.42 L /mol
Put values in above equation 1
Volume of gas = 4219 mol x 22.42 L /mol
Volume of gas = 94584 L
Volume of gas = 9.46 x 10⁴ L
So,
Volume of oxygen (O₂) = 9.46 x 10⁴ L
