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Calculate the energy, in electron volts, of a photon whose frequency is the following.

(a) 585 THz
(b) 3.50 GHz
(c) 40.0 MHz

Planck's equation for the energy of a photon is E = hf, where f is the frequency and h is Planck's constant. We use 1 eV = 1.60 ✕ 10−19 J for units of energy.

(a) For the energy of the photon at a frequency of 585 THz, we have E = hf

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Answer:

(a) [tex]E=2.42eV[/tex]

(b) [tex]E=1.45*10^{-5}eV[/tex]

(c) [tex]E=1.66*10^{-7}eV[/tex]

Explanation:

The Planck-Einstein relation allows us to know the energy (E) of a photon, knowing its frequency (f). According to this relation, the energy of the photon is defined as:

[tex]E=hf[/tex]

Here h is the Planck constant.

(a)

[tex]E=(4.14*10^{-15}eV\cdot s)(585*10^{12}Hz)\\E=2.42eV[/tex]

(b)

[tex]E=(4.14*10^{-15}eV\cdot s)(3.50*10^{9}Hz)\\E=1.45*10^{-5}eV[/tex]

(c)

[tex]E=(4.14*10^{-15}eV\cdot s)(40.0*10^{6}Hz)\\E=1.66*10^{-7}eV[/tex]

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