Answer:
The area of the rectangle is [tex]A=5L-L^2[/tex].
Step-by-step explanation:
The perimeter of a rectangle is
[tex]P=2(L+W)[/tex]
where, L is length and W is width.
It is given that perimeter of a rectangle is 10m.
[tex]10=2(L+W)[/tex]
Divide both sides by 2.
[tex]5=L+W[/tex]
Subtract L from both sides.
[tex]5-L=W[/tex]
Area of a rectangle is
[tex]A=L\times W[/tex]
Substitute W=(5-L) in the above formula.
[tex]A=L\times (5-L)[/tex]
[tex]A=5L-L^2[/tex]
Therefore, the area of the rectangle is [tex]A=5L-L^2[/tex].
