Explanation:
The minimum uncertainty position is 100 nm.
Therefore, by Heisenberg Uncertainty principal
ΔxΔp≥h/2
Δp≥h/(2Δx)
we know that
h= [tex]1.0546\times10^{-34}[/tex] Js
Δx= [tex]100\times10^{-12} m[/tex]
therefore,
[tex]\Delta p =\frac{1.0546\times10^{-34}}{2\times12\times10^{-12}} = 5.3\times10^{-25} kgms^{-1}[/tex]
therefore,
[tex]\Delta v= \frac{\Delta p}{m} =\frac{5.3\times10^{-25}}{9.11\times10^{-31}}= 5.8\times10^{5} ms^{-1}[/tex]
