Answer:
charge on the 24 nF capacitor is 84 nC
Explanation:
given data
capacitance Q1 = 16 nF
capacitance Q2 = 24 nF
charge on the 16 nF capacitor C1 = 56 nC
solution
we get here capacitor in parallel have same voltage
V1 = V2 ...............1
here voltage V1 = [tex]\frac{Q1}{C1}[/tex]
[tex]\frac{Q1}{C1}[/tex] = [tex]\frac{Q2}{C2}[/tex] .....................2
put here value we get
[tex]\frac{56}{16} = \frac{Q2}{24}[/tex]
Q = 84 nC
so charge on the 24 nF capacitor is 84 nC