Answer:
Force between two identical conducting ball will be [tex]2.65\times 10^{-5}N[/tex]
Explanation:
We have given there is two identical conducting small spheres having charge [tex]q_1=12nC=12\times 10^{-9}C[/tex] and [tex]q_2=-21nC=-21\times 10^{-9}C[/tex]
Distance between centers of the ball is 0.290 m
So r = 0.290 m
We have to fond the electric force between the balls
According to Coulomb's law force between two charges is given by
[tex]F=\frac{1}{4\pi \epsilon _0}\frac{q_1_2}{r^2}=\frac{Kq_1q_2}{r^2}[/tex]
So force [tex]F=\frac{9\times 10^{9}\times 12\times 10^{-9}\times 21\times 10^{-9}}{0.293^2}=2.65\times 10^{-5}N[/tex]
So force between two identical conducting ball will be [tex]2.65\times 10^{-5}N[/tex]
