Answer:
v = 18.92 m/s
Explanation:
given,
mass of the tomato = 185 g = 0.185 Kg
height of the lift, h = 15 m
work done by lifting the tomato will be equal to the potential energy gained by the tomato.
W = PE
W = m g h
W = 0.185 x 9.8 x 15
W = 27.195 J
now,
E = 82.1 % of KE
[tex]E = 0.821\times \dfrac{1}{2} m v^2[/tex]
[tex]27.195 = 0.821\times 0.5\times 0.185 \times v^2[/tex]
0.07594 v² = 27.195
v² = 358.099
v = 18.92 m/s
speed of the tomato at which it hits ground is equal to 18.92 m/s.
