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What is the equation of a line that passes through the point (10, 5) and is perpendicular to the
line whose equation is y= x-2?
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Respuesta :

Answer:

y = -x + 15

Step-by-step explanation:

y = x-2

slope = 1

perpendicular line slope = -1

pass point (10, 5)

y intercept = y - mx = 5 - (-1)x10  = 15

equation: y = mx + b

y = -x + 15

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