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A stretched string is fixed at both ends which are 160 cm apart. If the density of the string is 0.038 g/cm, and its tension is 600 N, what is the wavelength of the 6th harmonic?

Respuesta :

Answer:

wavelength of 6th harmonic will be 0.266 m

Explanation:

We have given string is fixed at both the end

So [tex]L=160cm=1.60m[/tex]

Density of string = 0.038 gram/cm

And tension T = 600 N

We have to find the wavelength of sixth harmonic

Wavelength of 6th harmonic will be [tex]\frac{1}{6}[/tex] times of the length of the string

So wavelength of the string will [tex]\lambda =\frac{L}{6}=\frac{1.60}{6}=0.266m[/tex]

So wavelength of 6th harmonic will be 0.266 m

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