A beam of monochromatic light is diffracted by a slit of width 0.580 mm. The diffraction pattern forms on a wall 1.56 m beyond the slit. The width of the central maximum is 2.05 mm.
Calculate the wavelength of the light.

Respuesta :

Answer:

 λ = 381 nm

Explanation:

given,

width of slit,a = 0.580 x 10⁻³ m

distance of the screen from the slit, D = 1.56 m

width of central maximum,y = 2.05 x 10⁻³ m

Distance of the edge of central maximum from center of the central maximum y ‘ = y/ 2  

                      Y ‘ = 1.025 x  10⁻³ m

for first maximum

d sin θ = λ

sin θ = tan θ = y'/D

[tex]\lambda = \dfrac{y'a}{D}[/tex]

[tex]\lambda = \dfrac{1.025\times 10^{-3}\times 0.580\times 10^{-3}}{1.56}[/tex]

 λ = 381 x 10⁻⁹ m

 λ = 381 nm

wavelength of light is equal to 381 nm.