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A 45.30 g sample of solid mercury is initially at –59.00°C. If the sample is heated at constant pressure ( = 1 atm), kJ of heat are needed to raise the temperature of the sample to 30.00°C.

Respuesta :

fidoskilee

Answer:

0.165kJ

Explanation:

Formula to use for such a question is;

Energy = number of mole x molar gas constant x change in temperature

Number of mole = reacting mass of mercury / molar mass of mercury = 45.30/200.58 = 0.226moles

Change in temperature = final temperature - initial temperature = 30 - (-59) =30 + 59 = 89 Kelvin

E = nRT = 0.226 x 8.314 x 89

Energy = 165.35Joules

Energy in kJ = 165.35/1000 = 0.165kJ