Which of the following would require the largest volume of 0.100 M sodium hydroxide solution for neutralization?:

(A) 20.0 mL of 0.0500 M nitric acid
(B) 15.0 mL of 0.0500 M hydrobromic acid
(C) 5.0 mL of 0.0100 M sulfuric acid
(D) 10.0 mL of 0.00500 M phosphoric acid

Respuesta :

Answer:10.0 mL of 0.00500 M phosphoric acid

Explanation:

If we look at the Ka values of the acids, we will realize that phosphoric acid has a Ka of 7.1 * 10-3. It is the only acid in the list having acid dissociation constant less than 1. This means that it does not ionize easily in solution and a very large volume of base must be added to ensure that it reacts completely. Acids with Ka >1 are generally regarded as strong acids. All the acids listed have Ka>1 except phosphoric acid.

The largest volume of 0.100 M sodium hydroxide solution for neutralization would be required by 20.0 mL of 0.0500 M nitric acid.

How to calculate volume?

The volume of a solution can be calculated using the following expression:

CaVa = CbVb

Where;

  • Ca = concentration of acid
  • Cb = concentration of base
  • Va = volume of acid
  • Vb = volume of base

According to this question, 0.100 M sodium hydroxide solution is given:

For nitric acid: 20 × 0.05 = 0.1 × Vb

Vb = 10mL

For hydrobromic acid: 15 × 0.05 = 0.1Vb

Vb = 7.5mL

For sulfuric acid: 5 × 0.01 = 0.1Vb

Vb = 0.5mL

For phosphoric acid: 10 × 0.005 = 0.1Vb

Vb = 0.5mL

Therefore, the largest volume of 0.100 M sodium hydroxide solution for neutralization would be required by 20.0 mL of 0.0500 M nitric acid.

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