Question :
The sum of three consecutive odd integers is 201. Find the integers.
Answer:
The Integers are 65,67,69.
Step-by-step explanation:
Let x be any number. when it is multiplied by 2 it becomes an even number.
So, 2x is an even number. Now adding an odd number to 2x , it becomes an odd number
so
First odd number be 2x+1
Second odd number be 2x+3
Third odd number be 2x+5
Now the sum of these three odd number gives 210,
That is
(2x+1) +(2x+3) +(2x+5) = 201
2x+1+2x+3+2x+5 =201
6x + 9 = 201
6x = 201- 9
6x = 192
[tex]x =\frac{192}{6}[/tex]
x = 32
Hence
The first odd number is (2x+1) = (2(32)+1) = 64+1 =65
The second odd number is (2x+3) = (2(32)+3) = 64+3 =67
The third odd number is (2x+1) = (2(32)+5) = 64+5 =69
