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A 200 kg chunck of lead falls from a hight of 30m and smashes into a rigid floor. calculate the increse in internal engery

Respuesta :

Answer:

[tex]\Delta E=58800\ J[/tex]

Explanation:

Given:

mass of lead chunk, [tex]m=200\ kg[/tex]

height of the fall, [tex]h= 30\ m[/tex]

  • Assuming the collision to be perfectly inelastic the whole kinetic energy of the chunk is lost after the collision.
  • Here when the chunk is at the given height it has a potential energy which on falling transforms into kinetic energy of the chunk.

So, increase in the internal energy of the system after the collision is :

[tex]\Delta E=m.g.h[/tex]

[tex]\Delta E=200\times 9.8\times 30[/tex]

[tex]\Delta E=58800\ J[/tex]

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