Person A can paint the neighbor's house 6 times as fast as Person B. The year A and B worked together it
took them 2 days. How long would it take each to paint the house?

Respuesta :

Person A takes 2.3 days to paint the house working alone

Person B takes 13.8 days to paint the house working alone

Solution:

Let "x" be the number of days it takes person A  to paint the house

Person A can paint the neighbor's house 6 times as fast as Person B

Therefore.

Number of days it takes person B to paint the house = 6x

Their rates of painting are added to get  the rate working together

[tex]\frac{\text{1 house}}{\text{x days}} + \frac{\text{1 house}}{\text{6x days}} = \frac{\text{1 house}}{\text{2 days}}[/tex]

[tex]\frac{1}{x} + \frac{1}{6x} = \frac{1}{2}\\\\\frac{1 \times 6}{6x} + \frac{1}{6x} = \frac{1}{2}\\\\\frac{7}{6x} = \frac{1}{2}\\\\\ x = \frac{7}{3}= 2.3[/tex]

Thus person A takes 2.3 days to paint the house working alone

Person B = 2x = 6(2.3) = 13.8

Thus person B takes 13.8 days to paint the house working alone