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A 0.500 kg mass is oscillating on a spring with k=330 N/m.The total energy of its oscillation is 3.24 J. What is speed of the mass when it is 0.100 m from the EP?
(Unit=m/s)

Respuesta :

The speed is 2.5 m/s

Explanation:

The total (mechanical) energy of the mass-spring system at any point during the motion is the sum of the kinetic energy (KE) and the potential energy (PE):

[tex]E=KE+PE=3.24 J[/tex]

and it is constant.

The kinetic energy can be written as

[tex]KE=\frac{1}{2}mv^2[/tex]

where

m = 0.500 kg is the mass

v is the speed

While the potential energy is

[tex]PE=\frac{1}{2}kx^2[/tex]

where

k = 330 N/m is the spring constant

x is the elongation

So the first equation becomes

[tex]E=\frac{1}{2}mv^2 + \frac{1}{2}kx^2[/tex]

Therefore, if we substitute

x = 0.100 m

We can find the speed when the elongation is x = 0.100 m:

[tex]v=\sqrt{\frac{2E-kx^2}{m}}=\sqrt{\frac{2(3.24)-(330)(0.100)^2}{0.500}}=2.5 m/s[/tex]

Learn more about kinetic and potential energy:

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Correct Answer:

2.5 m/s