Answer: m<ABC= 55 degrees
Step-by-step explanation:
m<CAD+m<ACD+m<ADC=180 degrees Sum of <'s in triangle
50+65+m<CDA=180 degrees substitution
m<CDA=65 Algebra
AC=AD=BC Def of Isos triangle
m<ACB+m< ABC+m<BAC=180 degrees Sum of <'s in triangle
m<ABC=m<CAB Def of Isos triangle
70+2m<ABC=180 Substitution
m<ABC=55 Algebra
