please help!!!!!!!!!!

Answer:
1-c
2-b
3-a
Step-by-step explanation:
1. 7y=14
y=2
-7y=-14
y=2
so the equation has one solution
2. 0=0
so the equation has infinite solution
3. 0=2 false
so the equation has no solution
1 solution
8x+7y=30
8x-7y=2
infinitely many solutions
-8x+7y=-2
8x-7y=2
no solution
8x-7y=2
-8x+7y=2
Explanation
The number of solutions of a pair of linear equations are determined by the following criteria
1 solution
-[tex]a1/a2 \neq b1/b2[/tex]
in the first pair [tex]a1/a2=8/8=1[/tex]
[tex]b1/b2=7/-7=-1[/tex]
therefore [tex]a1/a2 \neq b1/b2[/tex]
infinitely many solution
[tex]a1/a2=b1/b2=c1/c2[/tex]
In the second pair of equations -8x+7y+2=0 and 8x-7y-2=0
[tex]a1/a2=-8/8=-1\\b1/b2=7/-7=-1\\c1/c2=2/-2=-1[/tex]
since [tex]a1/a2=b1/b2=c1/c2[/tex], the pair of equations have infinitely many solutions
no solution
[tex]a1/a2=b1/b2\neq c1/c2[/tex]
in the third pair of equation
[tex]a1/a2=8/-8=-1\\b1/b2=-7/7=-1\\c1/c2=-2/-2=1[/tex]
Here [tex]a1/a2=b1/b2\neq c1/c2[/tex]