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Lisa and Jen left home at the same time, only Lisa biked to school at a speed of 10 mph while Jen just walked at a speed of 4 mph. How much time did it take Lisa to get to school if she reached school when Jen still was 1 mile away from it?

Lisa and Jen left home at the same time only Lisa biked to school at a speed of 10 mph while Jen just walked at a speed of 4 mph How much time did it take Lisa class=

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frika

Answer:

[tex]\dfrac{1}{6}[/tex] hour or [tex]10[/tex] minutes

Step-by-step explanation:

Lisa:

Rate = 10 mph

Time = t hours

Distance = x miles

[tex]x=10\cdot t[/tex]

Jen:

Rate = 4 mph

Time = t hours

Distance = x - 1 miles

[tex]x-1=4\cdot t[/tex]

Hence,

[tex]10t-1=4t\\ \\10t-4t=1\\ \\6t=1\\ \\t=\dfrac{1}{6}\ hour[/tex]

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