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A light bulb provides a resistance of 20 Ω to the 30 A current that runs through it. Determine the voltage of the battery in the flashlight.

0.7 V
2 V
51 V
600 V

Respuesta :

Explanation:

Ohm's law:

V = IR

V = (30 A) (20 Ω)

V = 600 V

Answer:

The voltage of the battery in the flashlight is 600 v

Explanation:

A light bulb provides a resistance of 20 Ω to the 30 A current that runs through it. Determine the voltage of the battery in the flashlight.

To determine the voltage of this battery,all we need to do is to use the formula;

V= IR

where v = voltage

I = current

R= resistance

From the question given;

resistance (I) is given to be 20   while current(I) is 30

We can now proceed to insert our values into the formula;

V= IR

V = 20 × 30

v = 600 v

The voltage of the battery in the flashlight is 600 v