the amount of a certain population with limited resources is given by the equation P= k/1+cB^-t solve this equation for the constant c. Write your answer so that there is no negative exponent.

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Answer:

Step-by-step explanation:

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The expression for the constant c with no negative exponent is expressed as [tex]c=\dfrac{B^t(k-P)}{P}[/tex]

The subject of the formula is a way of representing a variable in terms of other variables in a given equation.

Given the expression:

[tex]P=\dfrac{k}{1+cB^{-t}}[/tex]

We are to make the constant c the subject of the formula as shown:

Cross multiply

[tex]P(1+cB^{-t})=k\\[/tex]

Expand the bracket

[tex]P+PcB^{-t}=k\\PcB^{-t}=k-P\\cPB^{-t}=k-P[/tex]

Divide both sides by [tex]PB^{-t}[/tex]

[tex]\dfrac{cPB^{-t}}{PB^{-t}}= \dfrac{k-P}{PB^{-t}} \\\dfrac{c}{1} = \dfrac{k-P}{PB^{-t}} \\c= \dfrac{k-P}{PB^{-t}}\\[/tex]

Since [tex]B^{-t}=\frac{1}{B^t}\\[/tex]

The expression becomes:

[tex]c= \dfrac{k-P}{P*\frac{1}{B^t} }\\c= \dfrac{k-P}{\frac{P}{B^t} }\\c=\dfrac{B^t(k-P)}{P}[/tex]

Hence the expression for the constant c is expressed as [tex]c=\dfrac{B^t(k-P)}{P}[/tex]

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