Answer:
1) mass ZnO = 55.155 g
2) V SO2(g) = 18.289 L
Explanation:
1) Zn + H2O → ZnO + H2
∴ mass Zn = 41.6 g
∴ mm Zn = 65.38 g/mol
⇒ mol Zn = (41.6 g)(mol/61.38 g) = 0.678 mol Zn
⇒ mol ZnO = (0.678 mol Zn)(mol ZnO/mol Zn) = 0.678 mol ZnO
∴ mm ZnO = 81.38 g/mol
⇒ mass ZnO = (0.678 mol ZnO)(81.38 g/mol) = 55.155 g ZnO
2) S(s) + O2(g) → SO2(g)
∴ mass S(s) = 24 g
∴ T = 25°C ≅ 298 K
∴ P = 1 atm
∴ mm S(s) = 32.065 g/mol
⇒ mol S(s) = (24 g)(mol/32.065 g) = 0.7485 mol S(s)
⇒ mol SO2(g) = (0.7485 mol S(s))(mol SO2(g)/mol S(s)) = 0.7485 mol SO2(g)
ideal gas:
⇒ V SO2(g) = ((0.082 atm.L/K.mol)(298 K)(0.7485 mol))/(1 atm)
⇒ V SO2(g) = 18.289 L SO2(g)