Respuesta :

Larrysammz

Answer:

Step-by-step explanation:

  • pick like terms

x² +  b²/4a² = -c / a + b²/4a²

  • b²/4a² = (b/2a)²

x² + (b/2a)² = -c/a + (b/2a)²

(x + b/2a)² = -c/a + (b/2a)² =  -c / a + b²/4a² = (-4ac+ b²)/4a²

(x + b/2a)² =  (-4ac+ b²)/4a²

  • square root both sides

√{(x + b/2a)²} = √{(-4ac+ b²)/4a²}

x + b/2a = √(-4ac+ b²) / √(4a²) = √(-4ac+ b²) / 2a = √( b²-4ac) / 2a

x + b/2a  =  √( b²-4ac) / 2a

  • subtract b/2a from both sides

x + b/2a -b/2a  =  {√( b²-4ac) / 2a } -b/2a

x = -b/2a +   {√( b²-4ac) / 2a }

  • the l.c.m is the same

x = {-b±√( b²-4ac)}/2a

pstnonsonjoku

A quadratic equation is an equation of the sort; ax^2 + bx + c =0. It can be solved by the formula method.

What is a quadratic equation?

A quadratic equation is an equation of the sort; ax^2 + bx + c =0. One of the ways of solving a quadratic equation is the formula method which is being derived here.

From the step shown in the image in the question;

Collecting like terms;

x² +  b²/4a² = -c / a + b²/4a²

x² + (b/2a)² = -c/a + (b/2a)²

We can now write;

(x + b/2a)² = -c/a + (b/2a)²

Hence;

(x + b/2a)² =  (-4ac+ b²)/4a²

Taking the square root of both sides and solving for x

x =-b±√( b²-4ac)/2a

Learn more about quadratic formula: https://brainly.com/question/2263981

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