When a force of 10.0 newtons acts at an angle of 20.0 degrees from vertical.then the horizontal and vertical components of the force would be 3.42 N and 9.3969 N respectively
Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum. The mathematical expression for Newton's second law is as follows
F = m*a
where F represents the force applied
m is the mass of the object and a is the acceleration of the object.
As given in the problem a force of 10.0 newtons acts at an angle of 20.0 degrees from vertical
The vertical component of the force would be
Fv = Fcos20°
=10×0.93969
=9.3969 N
The horizontal component of the force would be
Fh = Fsin20°
= 10×0.3420
=3.42 N
Thus, When a force of 10.0 newtons acts at an angle of 20.0 degrees from vertical. then the horizontal and vertical components of the force are 3.42 N and 9.3969 N respectively
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