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Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation:
3N2H4(l)→4NH3(g)+N2(g)
2.6mol N2H4
4.05mol N2H4
63.8g N2H4

Respuesta :

taskmasters
The balanced chemical reaction is:

3N2H4(l)→4NH3(g)+N2(g)

The amounts given for the N2H4 reactant will be the starting point for our calculations.

2.6mol N2H4 ( 4 mol NH3 / 3 mol N2H4 ) = 3.47 mol NH3

4.05mol N2H4 ( 4 mol NH3 / 3 mol N2H4 ) = 5.4 mol NH3

63.8g N2H4  ( 4 mol NH3 / 3 mol N2H4 ) = 85.07 mol NH3

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