Respuesta :
The balanced chemical reaction is:
2HCl + Ca = CaCl2 + H2
We are given the amount of the reactants to be used for the reaction. These values will be the starting point of our calculations.
100 g HCl ( 1 mol HCl / 36.46 g HCl ) = 2.74 mol HCl
100 g Ca ( 1 mol Ca / 40.08 g ) = 2.08 mol Ca
From the reaction, the mole ratio of the reactants is 2:1 where every 2 moles of hydrochloric acid, 1 mole of calcium is required. Therefore, the limiting reactant for this case is calcium.
2HCl + Ca = CaCl2 + H2
We are given the amount of the reactants to be used for the reaction. These values will be the starting point of our calculations.
100 g HCl ( 1 mol HCl / 36.46 g HCl ) = 2.74 mol HCl
100 g Ca ( 1 mol Ca / 40.08 g ) = 2.08 mol Ca
From the reaction, the mole ratio of the reactants is 2:1 where every 2 moles of hydrochloric acid, 1 mole of calcium is required. Therefore, the limiting reactant for this case is calcium.
Answer: hydrochloric acid
Explanation: [tex]2HCl+Ca\rightarrow CaCl_2+H_2[/tex]
As can be seen from the chemical equation, 2 moles of hydrochloric acid react with 1 mole of calcium.
According to mole concept, 1 mole of every substance weighs equal to its molar mass.
Thus [tex]2\times 36.5=73 g[/tex] of of hydrochloric acid reacts with 40 g of calcium.
100 g of hydrochloric acid react with=[tex]\frac{40}{73}\times 100=54.79 g[/tex]of calcium
Thus HCl is the limiting reagent as it limits the formation of product and calcium is the excess reagent as (100-54.79)=45.21 g is left unreacted.