All steps that Marcie did are right, but she forgot to change sign in last step.
Consider the inequality
[tex] -2(x - 5) -12 \le 4 + 6(x + 3).[/tex]
Then
[tex] -2x+10-12 \le 4 + 6x+18.[/tex]
Group the numbers:
[tex] -2x-2 \le 6x+22.[/tex]
Separate terms with x and without x in different sides:
[tex] -2x-6x \le 22+2.\\-8x\le 24.[/tex]
The coefficient at x is -8 and it is negative, then dividing the inequality by -8 you have to change sign in opposite:
[tex] x\ge -3. [/tex]
Answer: Marcie forgot to change sign in last step.
