Answer-
[tex]\left(3x-6\right)\left(2x^2-7x+1\right)=6x^3-33x^2+45x-6[/tex]
Solution-
Given the two polynomials are [tex]3x-6, 2x^2 -7x+1[/tex]
So their product will be,
[tex]=\left(3x-6\right)\left(2x^2-7x+1\right)[/tex]
Distributing the Parentheses,
[tex]=3x\cdot \:2x^2+3x\left(-7x\right)+3x\cdot \:1+\left(-6\right)\cdot \:2x^2+\left(-6\right)\left(-7x\right)+\left(-6\right)\cdot \:1[/tex]
Applying minus-plus rules,
[tex]=3\cdot \:2x^2x-3\cdot \:7xx+3\cdot \:1\cdot \:x-6\cdot \:2x^2+6\cdot \:7x-6\cdot \:1[/tex]
Simplifying further,
[tex]=6x^3-33x^2+45x-6[/tex]
