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At a railway yard, locomotives are used to haul containers carrying oil. A locomotive is chosen according to the volume of oil it can haul, as shown in the table.


Locomotive

Capacity

A450 0−750 cubic feet
CG35 750−1,500 cubic feet
BR73 1,500−2,500 cubic feet
YH61 2,500−3,500 cubic feet


The four cylindrical containers listed in the table need to be hauled.


Cylinder

Length (ft.)

Diameter (ft.)

Fill Level

A 40 12 half
B 24 8 full
C 16 16 full
D 6 12 full


Match each container to the locomotive needed to haul it.





Tiles




A450



cylinder A



CG35



cylinder B



BR73



cylinder C



YH61



cylinder D

Respuesta :

nobillionaireNobley
Volume of cylinder A = π(12^2/4) x (40/2) = 2,262 cubic feet which will be hauled by locomotive BR73.
Volume of cylinder B = π(8^2/4) x 24 = 1,206 cubic feet which will be hauled by locomotive CG35.
Volume of cylinder C = π(16^2/4) x 16 = 3,217 cubic feet which will be hauled by locomotive YH61.
Volume of cylinder D = π(6^2/4) x 12 = 339 cubic feet which will be hauled by locomotive A450.

ayfat23

We can compare the volume with how they are going to be overhauled as :

  • cylinder A :locomotive BR73.
  • cylinder B :locomotive CG35.
  • Cylinder C ;locomotive YH61.
  • Cylinder D :locomotive A450.

What is Volume of cylinder ?

We can calculate the volume of the cylinder using the formula π[tex]r^{2}[/tex]h as :

For cylinder A:

[tex]\pi *12^{\frac{2}{4} } *20 =2262 ft^{3}[/tex]

For cylinder B;

[tex]\pi *8^{\frac{2}{4} } *24 =1206 ft^{3}[/tex]

For cylinder C;

[tex]\pi *16^{\frac{2}{4} } *16 =3217 ft^{3}[/tex]

For cylinder D:

[tex]\pi *6^{\frac{2}{4} } *12 =339 ft^{3}[/tex]

Then we can compare the volume with how they are going to be overhauled as :

cylinder A :locomotive BR73.

cylinder B :locomotive CG35.

Cylinder C ;locomotive YH61.

Cylinder D :locomotive A450.

Learn more on volume of the cylinder at ; https://brainly.com/question/9554871

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