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4 Jillian's school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket salesfor opening night totaled $2071.50. The equation 10.50a 3.75b 2071.50, where a is the number of adult ticketsA sold and b is the number of student tickets sold, can be used to find the number of adult and student tickets. If 82students attended, how may adult tickets were sold?adult tickets

4 Jillians school is selling tickets for a play The tickets cost 1050 for adults and 375 for students The ticket salesfor opening night totaled 207150 The equat class=

Respuesta :

$10.50a + $3.75b = $2,071.50 It is given that b = 82 Therefore - $10.50a + ($3.75)(82) = $2,071.50 or $10.50a + $307.50 = $2,071.50 $10.50a = $2,071.50 - $307.50 = $1,764.00 Therefore - a (number of adult tickets sold) = $1,764.00/$10.50 = 168 tickets

Answer: The number of adult tickets sold is 168.

Step-by-step explanation:  Given that the Jillian's school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students.

The ticket sales for opening night totaled $2071.50. The equation representing the situation is

[tex]10.50a+3.75b=2071.50~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]

where a is the number of adult tickets sold and b is the number of student tickets sold.

We are to calculate the number of adult tickets that were sold.

If 82 students attended, then b = 82.

Substituting the value of b in equation (i), we get

[tex]10.50a+3.75b=2071.50\\\\\Rightarrow10.50a+3.75(82)=2071.50\\\\\Rightarrow10.50a+307.5=2071.50\\\\\Rightarrow10.50a=2071.50-307.5\\\\\Rightarrow10.50a=1764\\\\\Rightarrow a=\dfrac{1764}{10.50}\\\\\Rightarrow a=168[/tex]

Thus, the number of adult tickets sold is 168.

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